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Question

Physics Question on laws of motion

The given figure is the part of a horizontally stretched net. Section ABAB is stretched with a force of 10N10 N. The tensions in the sections BCBC and BFBF are

A

10 N, 11 N

B

10 N, 6 N

C

10 N, 10 N

D

can't be calculated due to insufficient data

Answer

10 N, 10 N

Explanation

Solution

From the figure.

T1cos30=T2cos30T_{1}\, \cos \,30^{\circ} =T_{2} \,\cos\, 30^{\circ}
T1=T2=T\therefore \,T_{1} =T_{2}=T (Let)
Again T1sin30+T2sin30=10T_{1} \,\sin \,30^{\circ}+T_{2} \,\sin\, 30^{\circ}=10
2Tsin30=102 T \,\sin\, 30^{\circ}=10
2T.12=102 T . \frac{1}{2} =10
T=10N\Rightarrow\, T=10 \,N
\therefore Tension in section BCBC and BFBF are 10N10\, N and 10N10 \,N