Question

The geometry around boron in the product 'B' formed from the following reaction is $BF _3+ NaH \xrightarrow{450 K } A + NaF$ $A + NMe _3 \rightarrow B$

• A. trigonal planar
• B. tetrahedral
• C. pyramidal
• D. square planar

Answer 1

Answer: (B)

tetrahedral

Answer 2

$\text{The correct option is (B):}$ $tetrahedral$