Question

The general value of $\sin x\cos x = 2$ satisfying $\sin 2x = 4$ is.

• A. $\sec\theta + \tan\theta = \sqrt{3}$
• B. $\sec^{2}\theta - \tan^{2}\theta = 1$
• C. $\Rightarrow$
• D. $\sec\theta - \tan\theta = \frac{1}{\sqrt{3}}$

Answer 1

Answer: (C)

$\Rightarrow$

Answer 2

$\sin\theta = \frac{6}{4\sqrt{3}} = \frac{\sqrt{3}}{2}$

$\Rightarrow$ $\cos^{2}(A + B) + \sin^{2}(A + B) + \cos 2B = 0$ , $1 + \cos 2B = 0$

$\cos 2B = \cos\pi$ $2B = 2n\pi + \pi$.