Question
Mathematics Question on Differential equations
The general solution of the differential equation (x2 + 2)dy +2xydx = ex(x2+2)dx is
A
yx=ex(x2+x−4)+c
B
2xy = ex(x2-2x+4)+c
C
(x2+2)y=ex(x2-2x+4)+c
D
(x2+2)2y = ex(x2+2x-4)+c
Answer
(x2+2)y=ex(x2-2x+4)+c
Explanation
Solution
The correct option is(C) (x2+2)y=ex(x2-2x+4)+c