Question
Mathematics Question on Quadratic Equations
The general solution of the differential equation loge(dydx)=x+y is
A
(A) ex + e–y = C
B
(B) ex + ey = C
C
(C) ey + e–x = C
D
(D) e–x + e–y = C
Answer
(A) ex + e–y = C
Explanation
Solution
Explanation:
dydx=ex⋅ey⇒∫e−ydy.=∫exdx⇒ex+e−y=c