Question

The general solution of $\sqrt3\cos x+\sin x=\sqrt2$, for any integer “n” is

• A. $n\pi+\frac{\pi}{6}±\frac{\pi}{4}$
• B. $n\pi-\frac{\pi}{6}±\frac{\pi}{4}$
• C. $2n\pi-\frac{\pi}{6}±\frac{\pi}{4}$
• D. $2n\pi+\frac{\pi}{6}±\frac{\pi}{4}$

Answer 1

Answer: (D)

$2n\pi+\frac{\pi}{6}±\frac{\pi}{4}$

Answer 2

The correct option is (D) : $2n\pi+\frac{\pi}{6}±\frac{\pi}{4}$.