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Question: The general equation to a system of parallel chords in the parabola \({{y}^{2}}=\dfrac{25}{7}x\) is ...

The general equation to a system of parallel chords in the parabola y2=257x{{y}^{2}}=\dfrac{25}{7}x is 4xy+k=04x-y+k=0. What is the equation to the corresponding diameter?

Explanation

Solution

Hint: The diameter of a parabola is defined as a line bisecting the system of parallel chords of a parabola. For y2=4ax{{y}^{2}}=4ax, it is given by y=2amy=\dfrac{2a}{m} where mm is the slope of the chords.

Complete step-by-step answer:
It is given in the question that the general equation to a system of parallel chords in the parabola y2=257x{{y}^{2}}=\dfrac{25}{7}x is 4xy+k=04x-y+k=0.
We know that the general equation of a straight line is given by y=mx+cy=mx+c, where the term mmrepresents the slope of the line and the term cc represents the intercept.
We can convert the equation 4xy+k=04x-y+k=0 to the general form by rearranging the terms as below,
y=4x+ky=4x+k
When we compare the two equations, we get that the slope as m=4m=4.
We know that the general equation of the parabola is given by y2=4ax{{y}^{2}}=4ax. Now, let us consider the equation of the parabola given in the question, y2=257x{{y}^{2}}=\dfrac{25}{7}x.
Now, let us convert the given equation into the general form. For that, we have to multiply and divide the RHS by 44. This can be done as shown below,
y2=44×257x y2=4×(254×7)x y2=4×(2528)x \begin{aligned} & {{y}^{2}}=\dfrac{4}{4}\times \dfrac{25}{7}x \\\ & {{y}^{2}}=4\times \left( \dfrac{25}{4\times 7} \right)x \\\ & {{y}^{2}}=4\times \left( \dfrac{25}{28} \right)x \\\ \end{aligned}
On comparing the above equation of the parabola with the general form, we get that a=2528a=\dfrac{25}{28}.
We know that the equation of diameter of the parabola is given by y=2amy=\dfrac{2a}{m}. Therefore, we can substitute the values of m=4m=4 and a=2528a=\dfrac{25}{28} in it to get the diameter.
So, we get the diameter as

& y=\dfrac{2\times \dfrac{25}{28}}{4} \\\ & y=\dfrac{\dfrac{25}{14}}{4} \\\ & y=\dfrac{25}{56} \\\ \end{aligned}$$ Therefore, the diameter of the parabola obtained is $$y=\dfrac{25}{56}$$. Note: Diameter of a parabola is also defined as the locus of all the mid-points of a system of parallel chords of a parabola. So, there is an alternate method to solve this question. From the equation of chord, $x$ can be substituted in the equation of parabola to formulate a quadratic equation. The roots of which will be the ordinates of point of intersection. The locus of midpoint of these ordinates would give the diameter.