Solveeit Logo

Question

Question: The gas in vessel is subjected to a pressure of 20 atmosphere at a temperature 27°C. The pressure of...

The gas in vessel is subjected to a pressure of 20 atmosphere at a temperature 27°C. The pressure of the gas in a vessel after one half of the gas is released from the vessel and the temperature of the remainder is raised by 50°C is

A

8.5 atm

B

10.8 atm

C

11.7 atm

D

17 atm

Answer

11.7 atm

Explanation

Solution

PV=μRT=mMRTPV = \mu RT = \frac{m}{M}RTŽ PmTP \propto mT

Ž P2P1=m2m1T2T1=12×(273+27+50)(273+27)=712\frac{P_{2}}{P_{1}} = \frac{m_{2}}{m_{1}}\frac{T_{2}}{T_{1}} = \frac{1}{2} \times \frac{(273 + 27 + 50)}{(273 + 27)} = \frac{7}{12}

Ž P2=712P1=712×20=11.67atm.11.7atmP_{2} = \frac{7}{12}P_{1} = \frac{7}{12} \times 20 = 11.67atm. \approx 11.7atm