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Question

Physics Question on Oscillations

The fundamental frequency of a closed pipe is 220 Hz. If 14\frac{1}{4} of the pipe is filled with water, the frequency of the first overtone of the pipe now is

A

220 Hz

B

440 Hz

C

880 Hz

D

1760 Hz

Answer

880 Hz

Explanation

Solution

FundamentaI frequency of closed pipe \hspace25mm n =\frac{v}{4l}=220\, Hz \Rightarrow \hspace20mm v =220 \times 4l If 14\frac{1}{4} of the pipe is filled with water then remaining length of air column is 3l4.\frac{3l}{4}. Now, fundamental frequency =v4(3l4)=v3l=\frac{v}{4\big(\frac{3l}{4}\big)}=\frac{v}{3l} and First overtone= 3 ×\times fundamental frequency. \hspace35mm = 3 \times \frac{v}{3L} =\frac{3 \times 220 \times 4l}{3l}= 880\, Hz