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Question

Physics Question on Waves

The fundamental frequency of a closed pipe is 220Hz220 \,Hz. If 14\frac{1}{4} of the pipe is filled with water, the frequency of the first overtone of the pipe now is

A

220 Hz

B

440 Hz

C

880 Hz

D

1760 Hz

Answer

880 Hz

Explanation

Solution

Fundamental frequency of closed pipe n=v4l=220Hzn=\frac{v}{4 l}=220 Hz v=220×4l\Rightarrow v=220 \times 4 l If 14\frac{1}{4} of the pipe is filled with water then remaining length of air column is 3l4\frac{3 l}{4}. Now, fundamental frequency =v4(3l4)=v3l=\frac{v}{4\left(\frac{3 l}{4}\right)}=\frac{v}{3 l} and First overtone =3×=3 \times fundamental frequency. =3×v3L=3×220×4l3l=3 \times \frac{v}{3 L}=\frac{3 \times 220 \times 4 l}{3 l} =880Hz=880\, Hz