The function (x^x; x > 0) is strictly increasing at | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

The function $x^x; x > 0$ is strictly increasing at

A

$\forall x\in R$

B

$x<\frac{1}{e}$

C

$x>\frac{1}{e}$

D

$x<0$

Answer

$x>\frac{1}{e}$

Explanation

Solution

The correct answer is Option (C) : $x>\frac{1}{e}$