Question

The function $f(x) = \log(x + \sqrt{x^{2} + 1})$ is

• A. An even function
• B. An odd function
• C. Periodic function
• D. None of these

Answer 1

Answer: (B)

An odd function

Answer 2

$f(x) = \log(x + \sqrt{x^{2} + 1})$ and

$f( - x) = - \log(x + \sqrt{x^{2} + 1}) = - f(x)$, so $f(x)$ is an odd function.