Question
Question: The function f(x) = \(\frac { \ell \mathrm { n } ( \pi + x ) } { \ell \mathrm { n } ( e + x ) }\) ,...
The function f(x) = ℓn(e+x)ℓn(π+x) , x ≥ 0 is
A
Increasing on and decreasing on
B
Decreasing on [0,eπ) and increasing on [eπ,∞)
C
Increasing on [0, ∞)
D
Decreasing on [0, ∞)
Answer
Decreasing on [0, ∞)
Explanation
Solution
f '(x) =
Now π + x > e + x ⇒ ln(π+xe+x) < 0 f '(x) < 0
thus f(x) is decreasing.