Solveeit Logo

Question

Question: The function \(\frac{1}{3}\) is...

The function 13\frac{1}{3} is

A

Continuous at the origin

B

Discontinuous at the origin because |x| is discontinuous

there

C

Discontinuous at the origin because 12\frac{1}{2} is discontinuous there

D

Discontinuous at the origin because both |x| and limx0sin3x+sinxx\lim_{x \rightarrow 0}\frac{\sin 3x + \sin x}{x} are discontinuous there

Answer

Discontinuous at the origin because 12\frac{1}{2} is discontinuous there

Explanation

Solution

x| x | is continuous at x=0x = 0 and xx\frac { | x | } { x } is discontinuous at x=0x = 0

f(x)=x+xxf ( x ) = | x | + \frac { | x | } { x } is discontinuous at x=0x = 0 .