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Question

Mathematics Question on Differentiability

The function f(x)=x2+2x5 f (x) = x^2 + 2x - 5 is strictly increasing in the interval

A

(1,)(-1, \infty)

B

(,1)(-\infty, -1)

C

[1,)[-1, \infty)

D

(,1](-\infty, -1]

Answer

(1,)(-1, \infty)

Explanation

Solution

We have f(x)=x2+2x5 f(x) =x^{2}+2 x-5 f(x)=2x+2\Rightarrow \, f'(x) =2 x+2 =2(x+1)=2(x+1) f(x)0\therefore \, f'(x) \geq \,0 2(x+1)0 \Rightarrow 2(x+1) \geq\, 0 x+10 \Rightarrow x+1 \geq\, 0 x1\Rightarrow x \geq-1 \therefore f(x) is increasing on [1,)[-1, \infty)