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Question

Mathematics Question on Differentiability

The function f(x) = |x| + |1 − x| is:

A

continuous and differentiable at x = 0 only

B

continuous at x = 0 but nowhere differentiable

C

continuous everywhere and differentiable at all points except at x = 0

D

continuous but not differentiable at x = 1

Answer

continuous everywhere and differentiable at all points except at x = 0

Explanation

Solution

The function f(x)=x+1xf(x) = |x| + |1 - x| is the sum of two absolute value functions, which are continuous everywhere. However, absolute value functions are not differentiable at the points where their arguments are zero. Specifically:

  • x|x| is not differentiable at x=0x = 0.
  • 1x|1 - x| is not differentiable at x=1x = 1.

Thus, f(x)f(x) is continuous everywhere but differentiable at all points except at x=0x = 0 and x=1x = 1.