Solveeit Logo

Question

Mathematics Question on Functions

The function f(x)=sec[log(x+1+x2)]f\left(x\right) = \sec \left[\log\left(x+\sqrt{1+x^{2}}\right)\right] is

A

odd

B

even

C

neither odd nor even

D

constant

Answer

even

Explanation

Solution

f(x)=sec(ln(x+1+x2))f(x)=\sec \left(\ln \left(x+\sqrt{1+x^{2}}\right)\right)
=secx=\sec x (odd function)
== even function
secx\because \sec x is an even function.