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Question

Physics Question on Oscillations

The frequency of vibrating air column in closed organ pipe is n. If its length be doubled and radius halved, its frequency will be nearly

A

n

B

n/2

C

2 n

D

4 n

Answer

n/2

Explanation

Solution

Key Idea: Closed organ pipe has an antinode at its open end, and node at closed end. The distance between a node and antinode in closed pipe, λ/4=l\lambda /4=l \Rightarrow λ=4l\lambda =4l Fundamental frequency or the first harmonic of closed pipe is n=vλn=\frac{v}{\lambda } \therefore n=v4ln=\frac{v}{4l} When l2=2l1,r2=r12,n1=n{{l}_{2}}=2{{l}_{1}},{{r}_{2}}=\frac{{{r}_{1}}}{2},{{n}_{1}}=n \Rightarrow n1n2=l2l1\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{{{l}_{2}}}{{{l}_{1}}} \Rightarrow n2=n1l1l2=nl12l1=n2{{n}_{2}}={{n}_{1}}\frac{{{l}_{1}}}{{{l}_{2}}}=n\frac{{{l}_{1}}}{2{{l}_{1}}}=\frac{n}{2} Note: A closed pipe produces only odd harmonics.