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Question: The frequency of the line in the emission spectrum of hydrogen when the atoms of the gas contain ele...

The frequency of the line in the emission spectrum of hydrogen when the atoms of the gas contain electrons in the third energy level are

A

1.268×1014Hz1.268 \times 10^{14}Hzand2.864×1016Hz2.864 \times 10^{16}Hz

B

3.214×1010Hz3.214 \times 10^{10}Hzand1.124×1012Hz1.124 \times 10^{12}Hz

C

1.806×1012Hz1.806 \times 10^{12}Hzand6.204×1015Hz6.204 \times 10^{15}Hz

D

4.568×1014Hz4.568 \times 10^{14}Hzand2.924×1015Hz2.924 \times 10^{15}Hz

Answer

4.568×1014Hz4.568 \times 10^{14}Hzand2.924×1015Hz2.924 \times 10^{15}Hz

Explanation

Solution

If an electron is in 3rd orbit, two spectral lines are possible

(1) When it falls from 3rd orbit to 2nd orbit.

In equation ν=3.289×1015[1n121n22]\nu = 3.289 \times 10^{15}\left\lbrack \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right\rbrack

ν1=3.289×1015[122132]=3.289×1015×536=\nu_{1} = 3.289 \times 10^{15}\left\lbrack \frac{1}{2^{2}} - \frac{1}{3^{2}} \right\rbrack = 3.289 \times 10^{15} \times \frac{5}{36} = 4.568×1414Hz4.568 \times 14^{14}Hz

(2) When it falls from 3rd orbit to 1st orbit :

}{= 2.924 \times 10^{15}Hz}$$