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Question

Chemistry Question on Structure of atom

The frequency of light emitted for the transition n = 4 to n = 2 of He+He^+ isequalto the transition in H atom corresponding to which of the following?

A

n = 2 to n = 1

B

n = 3 to n = 2

C

n = 4 to n = 3

D

n = 3 to n = 1

Answer

n = 2 to n = 1

Explanation

Solution

hv=ΔE=13.6z2(1n121n22)hv = \Delta E = 13.6 \,z^{2} \left(\frac{1}{n^{2}_{1}}-\frac{1}{n^{2}_{2}}\right) He+=Hz2(1(n12)21(n22)2)\vee_{He+} = \vee_{H} � z^{2}\left(\frac{1}{\left(\frac{n_{1}}{2}\right)^{2}}-\frac{1}{\left(\frac{n_{2}}{2}\right)^{2}}\right) =H(1(22)21(42)2)= \vee_{H} \left(\frac{1}{\left(\frac{2}{2}\right)^{2}}-\frac{1}{\left(\frac{4}{2}\right)^{2}}\right) For H-atom n1=1,n2=2n_{1} = 1, n_{2} = 2