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Question

Physics Question on Ray optics and optical instruments

The frequency of a light wave in a material is 2×1014Hz2 \times 10^{14} Hz and wavelength is 5000?5000\, ?. The refractive index of material will be

A

1.4

B

1.5

C

3

D

1.33

Answer

3

Explanation

Solution

Velocity of light waves in material is
v=vλv=v \lambda ...(i)
Refractive index of material is
μ=cv\mu=\frac{c}{v} ...(ii)
where cc is speed of light in vacuum or air
or μ=cvλ\mu=\frac{c}{v \lambda} ...(iii)
Given, v=2×1014Hzv=2 \times 10^{14} Hz
λ=5000?=5000×1010m\lambda=5000 ?=5000 \times 10^{-10} m
c=3×108m/sc=3 \times 10^{8} m / s
Hence, from E (iii), we get
μ=3×1082×1014×5000×1010=3.00\mu=\frac{3 \times 10^{8}}{2 \times 10^{14} \times 5000 \times 10^{-10}}=3.00