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Question: The frequency of 1<sup>st</sup> line of Balmer series in \(H_{2}\) atom is \(\nu_{0}\). The frequenc...

The frequency of 1st line of Balmer series in H2H_{2} atom is ν0\nu_{0}. The frequency of line emitted by singly ionised He atom is.

A

2ν02\nu_{0}

B

4ν04\nu_{0}

C

ν0/2\nu_{0} ⥂ / ⥂ 2

D

ν0/4\nu_{0} ⥂ /4 ⥂

Answer

4ν04\nu_{0}

Explanation

Solution

νZ2νH2νHe=(12)2=14νHe=4νH2\nu \propto Z^{2} \Rightarrow \frac{\nu_{H_{2}}}{\nu_{He}} = \left( \frac{1}{2} \right)^{2} = \frac{1}{4} \Rightarrow \nu_{He} = 4\nu_{H_{2}}= 4ν0