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Question: The freezing point on a thermometer is marked as 20<sup>0</sup> and the boiling point as 150<sup>0</...

The freezing point on a thermometer is marked as 200 and the boiling point as 1500. A temperature of 600C on this thermometer will be read as –

A

400

B

650

C

980

D

1100

Answer

980

Explanation

Solution

θ2015020\frac{\theta - 20}{150 - 20} = 6001000\frac{60 - 0}{100 - 0}

q – 20 = 1310\frac{13}{10} × 60 = 78

q = 980