Question
Question: The freezing point on a thermometer is marked as 20<sup>0</sup> and the boiling point as 150<sup>0</...
The freezing point on a thermometer is marked as 200 and the boiling point as 1500. A temperature of 600C on this thermometer will be read as –
A
400
B
650
C
980
D
1100
Answer
980
Explanation
Solution
150−20θ−20 = 100−060−0
q – 20 = 1013 × 60 = 78
q = 980