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Question: The freezing point on a thermometer is marked as 20<sup>0</sup> and the boiling point at as 150<sup>...

The freezing point on a thermometer is marked as 200 and the boiling point at as 1500. A temperature of 600C on this thermometer will be read as

A

400

B

650

C

980

D

1100

Answer

980

Explanation

Solution

Temperature on any scale can be converted into other scale by X−LFPUFP−LFP\frac{X - LFP}{UFP - LFP} = Constant for all scales

∴\therefore X−20∘150∘−20∘=C−0∘100∘−0o\frac{X - 20{^\circ}}{150{^\circ} - 20{^\circ}} = \frac{C - 0{^\circ}}{100{^\circ} - 0^{o}} ⇒ X = C×130∘100∘+20∘\frac{C \times 130{^\circ}}{100{^\circ}} + 20{^\circ} = 60∘×130∘100∘+20∘=98∘\frac{60{^\circ} \times 130{^\circ}}{100{^\circ}} + 20{^\circ} = 98{^\circ}