Question

The freezing point of the 0.05 molal solution of non - electrolyte in water is? (kf = 1.86)

Answer 1

To calculate the freezing point of a solution, we can use the formula:
ΔTf = Kf x m
Given: Kf = 1.86 (in units of molal per degree Celsius)
m = 0.05 molal
Substituting the given values into the formula, we get:
ΔTf = 1.86 x 0.05
ΔTf = 0.093oC
The freezing point depression (ΔTf) is 0.093oC
Freezing point of the solution = Freezing point of water - ΔTf
Freezing point of the solution = 0oC - 0.093oC = -0.093oC
Freezing point of the 0.05 molal solution of the non-electrolyte in water is approximately -0.093oC.
freezing point (Δ Tf ​) can be calculated using the formula Δ Tf ​=kf ​× m , where kf ​ is the cryoscopic constant and m is the molality. For the given values kf =1.86 and m =0.05, the calculation yields Δ Tf ​=0.093.
Thus, the final freezing point (Tf ​) is found by subtracting 0.0930.093 from the initial temperature,