Question

The fractional change in the value of free-fall acceleration 'g' for a particle when it is lifted from the surface to an elevation h (h<<R) is

• A. $\frac { \mathrm { h } } { \mathrm { R } }$
• B.
• C.
• D. None of these.

Answer 1

Answer: (B)

Answer 2

putting dR = h we orbit

$\Rightarrow$ $\frac { d g } { h } = \frac { - 2 G M } { R ^ { 2 } } \frac { 1 } { R }$ $\Rightarrow$