Question
Chemistry Question on Atomic Structure
The four quantum numbers for the electron in the outer most orbital of potassium (atomic no. 19) are
A
n=4,l=2,m=−1,s=+21
B
n=4,l=0,m=0,s=+21
C
n=3,l=0,m=1,s=+21
D
n=2,l=0,m=0,s=+21
Answer
n=4,l=0,m=0,s=+21
Explanation
Solution
The electron configuration for potassium (K, atomic number 19) is:
K:1s2,2s2,2p6,3s2,3p6,4s1.
The outermost orbital is the 4s orbital. The quantum numbers for the outermost electron are:
n=4,l=0,m=0,s=+21.