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Question: The four distinct points (0, 0),(2, 0), (0, –2) and (k,–2)are con-cyclic, if k =...

The four distinct points (0, 0),(2, 0), (0, –2) and (k,–2)are con-cyclic, if k =

A

–2

B

2

C

1

D

0

Answer

2

Explanation

Solution

The equation of circle passing through (0,0),(2,0)( 0,0 ) , ( 2,0 ) and (0, – 2) is x2+y22x+2y=0x ^ { 2 } + y ^ { 2 } - 2 x + 2 y = 0. If it passes through (k,2)( k , - 2 ) , then k2+42k4=0k ^ { 2 } + 4 - 2 k - 4 = 0 k=0,2\Rightarrow k = 0,2

(0,2)( 0 , - 2 ) is already a point on circle \therefore k = 2.