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Question: The formula of oxide of potassium with percentage of oxygen being \(45.07\% \) is: A.\({{\text{K}}...

The formula of oxide of potassium with percentage of oxygen being 45.07%45.07\% is:
A.K2O{{\text{K}}_{\text{2}}}{\text{O}}
B.KO2{\text{K}}{{\text{O}}_{\text{2}}}
C.K2O2{{\text{K}}_{\text{2}}}{{\text{O}}_{\text{2}}}
D.None of these

Explanation

Solution

Percentage of an element in the compound is calculated as the ratio of mass of that element in the compound to the total mass of the compound multiplied by 100100. Total mass of the compound is calculated as the sum of the masses of all elements present in the compound.

Complete step by step answer:
First of all let us read about molecular formulas.
Molecular weight of the substance: It is defined as the sum of the molecular masses of all elements present in the substance.
Number of moles: It is defined as the ratio of mass of the substance to the molecular mass of the substance.
Molecular formula: The molecular composition in the compound is known as molecular formula. For example: the molecule of water is H2O{H_2}O i.e. two atoms of hydrogen with oxygen.
Here in the question we are given the compound of potassium and oxygen and also we know the molecular weight of potassium which is 3939 and molecular weight of oxygen is 1616. In the question we are given with the percentage of oxygen as 45.07%45.07\% .
In option A) K2O{{\text{K}}_{\text{2}}}{\text{O}} the percentage of oxygen is as 1694×100=17.02%\dfrac{{16}}{{94}} \times 100 = 17.02\% , where 1616 is the molecular weight of oxygen and 9494 is the molecular weight of K2O{K_2}O.
In option B) KO2{\text{K}}{{\text{O}}_2} the percentage of oxygen is as 3271×100=45.07%\dfrac{{32}}{{71}} \times 100 = 45.07\% , where 3232 is the molecular weight of oxygen and 7171 is the molecular weight of KO2K{O_2}.
In option C) K2O2{K_2}{O_2} the percentage of oxygen is as 32110×100=29.09%\dfrac{{32}}{{110}} \times 100 = 29.09\% , where 3232 is the molecular weight of oxygen and 110110 is the molecular weight of K2O2{K_2}{O_2}.

So option B is correct i.e. KO2K{O_2}. Hence the formula of oxide of potassium with percentage of oxygen being 45.07%45.07\% is KO2K{O_2}.

Additional information:
Atoms: It is the smallest unit of an element. The elements are made of the same kind of atoms. In the atoms there are three particles: electrons, protons and neutrons.
Electrons: They are the negatively charged particle having negligible mass. They move in the atoms outside the nucleus in a fixed orbit.
Protons: They are positively charged particles. They have mass. They are present in the nucleus (a special room in the atoms were neutrons and protons are present).
Neutrons: They have no charge but they have mass. They are also present in the nucleus along with protons.
Gram molecule: It is defined as the number of grams of the substance i.e. the molecular mass of the substance.
Atomic mass: It is defined as the total number of protons and neutrons present in the nucleus of an atom. It is represented by symbol A.
Atomic number: It is defined as the number of protons in the nucleus of an atom. It is represented by symbol Z.

Note:
Formula mass: It is defined as the sum of the atomic weights of all the atoms present in the compound. And if the compound is covalent in nature then the formula mass is known as molecular mass and if we are calculating mass of one mole of substance then it is known as molar mass.