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Question: The formula of metal oxide of a metal A is \({A_2}{O_3}\). Determine the formula of its phosphate. ...

The formula of metal oxide of a metal A is A2O3{A_2}{O_3}. Determine the formula of its phosphate.
A) A3PO4{A_3}P{O_4}
B) A2(PO4)2{A_2}{(P{O_4})_2}
C) A(PO)2A{(PO)_2}
D) APO4AP{O_4}

Explanation

Solution

The measurement of the net electric charge of a valence electron is called the electron valency, it also indicates the number of electrons necessary for an ion in order to attain a balanced electric charge. Also, the atoms having almost full or almost empty valence shells always tend to be more reactive.

Complete solution:
The valency of an atom is the number of electrons needed to be gained or lost in order to attain a noble gas electronic configuration. The valency of an element will always be a whole number and sometimes an element exhibits more than one valency.
In the given metal oxide A2O3{A_2}{O_3}
We know that o2{o_2} has a valency of -2 and in order to attain a balanced state for the metal oxide AA must have a valency of +3.
Also, we know that phosphate (PO4P{O_4}) has a valency of -3 and when the metal AA combine with the phosphate in order to form the corresponding metal phosphate it will be having a chemical formula APO4AP{O_4}
\therefore Option D is the correct answer.

Additional information: The atom or molecule with zero valency shows the absence of net electric charge. The valency of an element or ion is determined by its outermost electrons and this measure shows the ability of an element to combine with other elements.

Note: Metals present in the first column of the periodic table have an electron valency of +1 and whereas the noble gas have an electron valency of 0 and are inert. Octet rule is the rule that ensures the outermost shell of a molecule or ion is having 8 electrons in the outermost shell.