Question
Mathematics Question on Differentiability
The formula for lagrange's mean value theorem is
A
f1(c)=f(a)+f(b)/b+a
B
f1(c)=t(a)+f(b)/b-a
C
f'1(c)=f(b)+f(a)/b-a
D
f'(c)=f(a)+f(b)/b+a
Answer
f'1(c)=f(b)+f(a)/b-a
Explanation
Solution
The correct option is (C): f'1(c)=f(b)+f(a)/b-a