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Question: The formula for critical velocity is: A.) \(\sqrt{2Rg}\) B.) \(\dfrac{R}{g}\) C.) \(\dfrac{3R}...

The formula for critical velocity is:
A.) 2Rg\sqrt{2Rg}
B.) Rg\dfrac{R}{g}
C.) 3R2g\dfrac{3R}{2g}
D.) Rg\sqrt{Rg}

Explanation

Solution

Hint: Study about the centripetal force and the gravitational force. Study how the satellite or any object moving in a circular direction around another object works. Think about which critical velocity you are asked by looking at the equations given as options.
Formula used:

g=GMR2g=\dfrac{GM}{{{R}^{2}}}
Vc2=GMR{{V}_{c}}^{2}=\dfrac{GM}{R}

Complete step by step answer:
To put a satellite into a stable orbit around earth we gave them a constant horizontal velocity. The minimum velocity required to make them orbit in the stable orbit is called the critical velocity.
Consider an object of mass m orbiting another object of mass M. For the circular motion we need a centripetal force. In this case we have the necessary centripetal force due to the gravitational attraction.

Let the orbiting object is at a distance R from the object in the centre.

Now, for the motion to be stable the centripetal force should be equal to the gravitational attraction.

centripetal force = gravitational force mVc2R=GMmR2 Vc2=GMR \begin{aligned} & \text{centripetal force = gravitational force} \\\ & \dfrac{m{{V}_{c}}^{2}}{R}=G\dfrac{Mm}{{{R}^{2}}} \\\ & {{V}_{c}}^{2}=\dfrac{GM}{R} \\\ \end{aligned}

Where, G is the gravitational constant and Vc{{V}_{c}} is the critical velocity of the object.
Now, we can express the acceleration due to gravity as

g=GMR2 so, G=gR2M \begin{aligned} & g=\dfrac{GM}{{{R}^{2}}} \\\ & \text{so,} \\\ & G=\dfrac{g{{R}^{2}}}{M} \\\ \end{aligned}

Now, putting the value of G in terms of g we get that,

Vc2=GMR Vc2=gR2MMR Vc2=gR Vc=gR \begin{aligned} & {{V}_{c}}^{2}=\dfrac{GM}{R} \\\ & {{V}_{c}}^{2}=\dfrac{g{{R}^{2}}}{M}\dfrac{M}{R} \\\ & {{V}_{c}}^{2}=gR \\\ & {{V}_{c}}=\sqrt{gR} \\\ \end{aligned}

So, the correct option is (D)

Note: Critical velocity can also be defined as the maximum velocity with which a liquid can flow through a tube without being turbulent.

Vc=Reηρr{{V}_{c}}=\dfrac{{{R}_{e}}\eta }{\rho r}

Where, Re{{R}_{e}}is the Reynolds number, η\eta is the viscosity, ρ\rho is the density of the fluid and r is the radius of the tube.

Do not confuse this critical velocity of fluid with the above critical velocity for circular motion.