The formation of ( O^{+}\_2 \[P\_t F\_6 ]^-) is the basis fo... | Chemistry | SolveeIt

The formation of $O^{+}_2 [P_t F_6 ]^-$ is the basis for the formation of Xenon fluorides. This is because

$O_2$ and $Xe$ have comparable sizes

$O_2$ and $Xe$ are gases

$O_2$ and $Xe$ have comparable ionisation energies

$O_2$ and $Xe$ have comparable electronegativities

Answer

$O_2$ and $Xe$ have comparable ionisation energies

Explanation

The first ionisation energy of xenon is quite close to that of oxygen and the molecular diameter of xenon and oxygen are almost identical.

Based on the above facts it is suggested that since oxygen combines with $PtF_6$ , so xenon should also form similar compound with $PtF_6$

Chemistry Question on p -Block Elements