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Question

Physics Question on thermal properties of matter

The formation of ice is started in a lake with water at 0C0^{\circ} C. When the atmospheric temperature is 10C-10^{\circ} C. If time taken for 1cm1 \,cm of ice to be formed is 77 hours, the time taken for the thickness of ice to increase from 1cm1 \,cm to 2cm2 \,cm is :

A

less than 7 hours

B

7 hours

C

more than 14 hours

D

more than 7 hours but less than 14 hours

Answer

more than 14 hours

Explanation

Solution

We know that the time of formation of ice in a lake from thickness y1y_{1} to y2y_{2} is directly proportional to (y22y12)t1\left(y_{2}{ }^{2}-y_{1}{ }^{2}\right) \propto t_{1} \ldots (i) Again, (y32y22)t2\left(y_{3}{ }^{2}-y_{2}{ }^{2}\right) \propto t_{2} \ldots (ii) Given: y1=0cm,y2=1cmy_{1}=0 cm , y_{2}=1 cm y3=2cm,t1=7y_{3}=2 cm , t_{1}=7 hour,t2=?t_{2}=? From (i) and (ii), we get y32y22y22y12=t27\frac{y_{3}{ }^{2}-y_{2}{ }^{2}}{y_{2}{ }^{2}-y_{1}{ }^{2}}=\frac{t_{2}}{7} or 22121202=t27\frac{2^{2}-1^{2}}{1^{2}-0^{2}}=\frac{t_{2}}{7} or 31=t27\frac{3}{1}=\frac{t_{2}}{7} Hence, t2=7×3=21t_{2}=7 \times 3=21 hour