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Question

Physics Question on mechanical properties of solids

The force required to stretch a wire of cross-section 1cm21 cm ^2 to double its length will be: (Given Yong's modulus of the wire =2×1011N/m2=2 \times 10^{11} N / m ^2 )

A

1×107N1 \times 10^7 N

B

1.5×107N1.5 \times 10^7 N

C

2×107N2 \times 10^7 N

D

2.5×107N2.5 \times 10^7 N

Answer

2×107N2 \times 10^7 N

Explanation

Solution

From the given options the correct answer is option (C): 2×107N2 \times 10^7 N