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Question: The force required to stretch a steel wire of 1 cm<sup>2</sup> cross-section to 1.1 times its length...

The force required to stretch a steel wire of 1 cm2 cross-section to 1.1 times its length would be (Y=2×1011Nm−2)(Y = 2 \times 10^{11}Nm^{- 2})

A

2×106N2 \times 10^{6}N

B

2×103N2 \times 10^{3}N

C

2×10−6N2 \times 10^{- 6}N

D

2×10−7N2 \times 10^{- 7}N

Answer

2×106N2 \times 10^{6}N

Explanation

Solution

L2=1.1L1∴Strain =lL1=L2−L1L1=1.1L1−L1L1L_{2} = 1.1L_{1}\therefore\text{Strain } = \frac{l}{L_{1}} = \frac{L_{2} - L_{1}}{L_{1}} = \frac{1.1L_{1} - L_{1}}{L_{1}}= 0.1.

F=YAlL=2×1011×1×10−4×0.1F = YA\frac{l}{L} = 2 \times 10^{11} \times 1 \times 10^{- 4} \times 0.1 =2×106N= 2 \times 10^{6}N.