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Question: The force required to just move a body up the inclined plane is double the force required to just pr...

The force required to just move a body up the inclined plane is double the force required to just prevent the body from sliding down the plane. The coefficient of friction is µ. The inclination q of the plane is –

A

tan–1 µ

B

tan–1 (µ/2)

C

tan–1 2µ

D

tan–1 3µ

Answer

tan–1 3µ

Explanation

Solution

Force required to prevent sliding

F = mg sin q – µ mg cos q

Force required to move upwards

F' = mg sin q + µ mg cos q

given F′=2 F\mathrm { F } ^ { \prime } = 2 \mathrm {~F}