Question

The force F is given in terms of time t and displacement x by the equation F = A cosBx + C sin DT. The dimensional formula of D/B is

• A. $\lbrack M^{0}L^{0}T^{0}\rbrack$
• B. $\lbrack M^{0}L^{0}T^{1}\rbrack$
• C. $\lbrack M^{0}L^{\text{-1}}T^{0}\rbrack$
• D. $\lbrack M^{0}L^{1}T^{\text{-1}}\rbrack$

Answer 1

Answer: (D)

$\lbrack M^{0}L^{1}T^{\text{-1}}\rbrack$

Answer 2

Bx = q (constant);x = L^–1

DT = q (constant); D = T^–1

$\frac{D}{B}$ = $\frac{T^{- 1}}{L^{- 1}}$ = LT^–1