Solveeit Logo
Login

Question

Question: The force constant of a wire is k and that of another wire is \(2 k\) When both the wires are stre...

The force constant of a wire is k and that of another wire is 2k2 k When both the wires are stretched through same distance, then the work done

A

W2=2W12W _ { 2 } = 2 W _ { 1 } ^ { 2 }

B

W2=2W1W _ { 2 } = 2 W _ { 1 }

C

W2=W1W _ { 2 } = W _ { 1 }

D

W2=0.5W1W _ { 2 } = 0.5 W _ { 1 }

Answer

W2=2W1W _ { 2 } = 2 W _ { 1 }

Explanation

Solution

W=12kx2W = \frac { 1 } { 2 } k x ^ { 2 }

If both wires are stretched through same distance then W∝kW \propto k. As k2=2k1k _ { 2 } = 2 k _ { 1 } so W2=2W1W _ { 2 } = 2 W _ { 1 }