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Question: The force between two small charged spheres having charges of \(1 \times 10^{- 7}C\) and \(2 \times ...

The force between two small charged spheres having charges of 1×10−7C1 \times 10^{- 7}C and 2×10−7C2 \times 10^{- 7}Cplaced 20 cm apart in air is.

A

4.5×10−2N4.5 \times 10^{- 2}N

B

4.5×10−3N4.5 \times 10^{- 3}N

C

5.4×10−2N5.4 \times 10^{- 2}N

D

5.4×10−3N5.4 \times 10^{- 3}N

Answer

4.5×10−3N4.5 \times 10^{- 3}N

Explanation

Solution

: Here, q1=1×10−7C,q2=2×10−7C,q_{1} = 1 \times 10^{- 7}C,q_{2} = 2 \times 10^{- 7}C, $$r = 20cm = 20 \times 10^{- 2}m

As F=q1q24πε0r2F = \frac{q_{1}q_{2}}{4\pi\varepsilon_{0}r^{2}}

=9×109×1×10−7×2×10−7(20×10−2)2=4.5×10−3N= \frac{9 \times 10^{9} \times 1 \times 10^{- 7} \times 2 \times 10^{- 7}}{(20 \times 10^{- 2})^{2}} = 4.5 \times 10^{- 3}N