Question

The force acting on a window of area $50 \mathrm {~cm} \times 50 \mathrm {~cm}$ of submatine at a depth of 2000 m in an ocean, the interior of which is maintained at seal level atomospheric pressure is (Density of sea water$= 10 ^ { 3 } \mathrm {~kg} \mathrm {~m} ^ { - 3 } , \mathrm {~g} = 10 \mathrm {~ms} ^ { - 2 }$

• A. $5 \times 10 ^ { 5 } \mathrm {~N}$
• B. $25 \times 10 ^ { 5 } \mathrm {~N}$
• C. $5 \times 10 ^ { 6 } \mathrm {~N}$
• D. $25 \times 10 ^ { 6 } \mathrm {~N}$

Answer 1

Answer: (C)

$5 \times 10 ^ { 6 } \mathrm {~N}$

Answer 2

Here,

The pressure outside the submarine is

Where is the atmospheric pressure

Pressure inside the submarine is

Hence net pressure acting on the window is gauge pressure.

Gauge pressure

Area of a window is

Force acting on the window is