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Chemistry Question on Bohr’s Model for Hydrogen Atom

The following reactions show the H2O2H_{2}O_{2} behaviour in I and II reactions as: I. PbS(s)+4H2O2(aq)→PbSO4(s)+4H2O(l)PbS(s) + 4 H_{2}O_{2} (aq) \to PbSO_{4}(s) + 4H_{2}O(l) II. HOC1+H2O2→H3O++Cl−+O2HOC1 + H_{2}O_{2} \to H_{3}O^{+} + Cl^{-} + O_{2}

A

Oxidising in acidic medium and reducing in basic medium

B

Reducing in acidic-medium and oxidising in basic medium

C

Oxidising in acidic medium and reducing in acidic medium

D

Reducing in acidic medium and oxidising in acidic medium

Answer

Oxidising in acidic medium and reducing in acidic medium

Explanation

Solution

Hydrogen peroxide, H2O2H_{2}O_{2} oxidises lead sulphide, PbS(s)PbS (s) to lead sulphate, PbSO4(s)PbSO_{4} (s) in acidic medium
PbS(s)Black+4H2O2(aq)→PbSO4(s)white+4H2O(l)\underset{\text{Black}}{{PbS(s)}}+4H_{2}O_{2}(aq) \to\underset{\text{white}}{{PbSO_{4}}(s)} + 4H_{2}O(l)
It reacts with hypochlorous acid, HOClHOCl to produce water, oxygen and hydrochloric acid, showing oxidising action in acidic medium
HOCl+H2O2→H3O++Cl−+O2HOCl+H_{2}O_{2} \to H_{3}O^{+}+Cl^{-}+O_{2}