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Question

Physics Question on Surface tension

The following observations were taken for determining surface tension T of water by capillary method: diameter of capillary, D=1.25×102mD = 1.25 \times 10^{-2} \, mrise of water, h=1.45×102mh = 1.45 \times 10^{-2} m. Using g=9.80m/s2g = 9.80 \, m/s^2 and the simplified relation T=rhg2×103N/mT = \frac{rhg}{2} \times 10^3 \, N/m , the possible error in surface tension is closest to:

A

0.15%0.15\%

B

1.5%1.5\%

C

2.4%2.4\%

D

10%10\%

Answer

1.5%1.5\%

Explanation

Solution

ΔTT×100=ΔDD×100+Δhh×100\frac{\Delta T}{T} \times100 = \frac{\Delta D}{D} \times100 + \frac{\Delta h}{h} \times100

=0.011.25×100+0.011.45×100= \frac{0.01}{1.25} \times100 + \frac{0.01}{1.45} \times100

=100125+100145= \frac{100}{125} + \frac{100}{145}

=0.8+0.689= 0.8 + 0.689

=1.489= 1.489 1.5%\simeq 1.5 \%