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Question: The following four wires of length L and radius r are made of the same material. Which of these will...

The following four wires of length L and radius r are made of the same material. Which of these will have the largest extension, when the same tension is applied?

A

L=100 cm, r=0.2 mmL = 100\text{ cm, }r = 0.2\text{ mm}

B

L=200 cm, r=0.4 mmL = 200\text{ cm, }r = 0.4\text{ mm}

C

L=300 cm, r=0.6 mmL = 300\text{ cm, }r = 0.6\text{ mm}

D

L=400 cm, r=0.8 mmL = 400\text{ cm, }r = 0.8\text{ mm}

Answer

L=100 cm, r=0.2 mmL = 100\text{ cm, }r = 0.2\text{ mm}

Explanation

Solution

: Young’s modulus, Y=FALΔL=Tπr2LΔLY = \frac{F}{A}\frac{L}{\Delta L} = \frac{T}{\pi r^{2}}\frac{L}{\Delta L}

ΔL=Tπr2LY\Delta L = \frac{T}{\pi r^{2}}\frac{L}{Y}

Where the symbols have their usual meanings.

As the four wires are made of the same material therefore Young’s modulus is the same for four wires. As the T and Y are the same for the four wires.

ΔLLr2\therefore\Delta L \propto \frac{L}{r^{2}}

Lr2\frac{L}{r^{2}}is maximum for wire of length L = 100 cm and radius r = 0.2 mm