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Question

Physics Question on physical world

The following figure gives the movement of an object. Select the correct statement from the given choices.

A

The total distance travelled by the object is 975 m

B

The maximum acceleration of the object is 2m/s22m/s^2

C

The maximum declaration happend between 25th25^{th} and 35th35^{th} seconds

D

The object was at rest between 10th10^{th} and 15th15^{th} seconds

Answer

The total distance travelled by the object is 975 m

Explanation

Solution

The total distance travelled by the object will be area of given graph in the figure.
So, the total distance travelled by the object
== Area of (1)+(1)+ Area of (2)+(2)+ Area of (3)+(3)+ Area of (4)(4)
++ Area of (5)+(5)+ Area of (6)+(6)+ Area of (7)(7)
=12×10×15+(2010)×(150)=\frac{1}{2} \times 10 \times 15+(20-10) \times(15-0)
+12m(2515)×(4015)+(3525)+\frac{1}{2 m}(25-15) \times(40-15)+(35-25)
(200)+12(3525)×(4020)+(20-0) +\frac{1}{2}(35-25) \times(40-20)+
(4535)×(200)+12(45-35) \times(20-0)+\frac{1}{2}
(5045)×(150)(50-45) \times(15-0)
=975m=975\, m