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Question: The following E0 values : \(E_{Fe^{3 +}/Fe^{2 +}}^{0} = + 0.77V; E_{Sn^{2 +}/Sn}^{0} = - 0.14V\) Un...

The following E0 values :

EFe3+/Fe2+0=+0.77V;ESn2+/Sn0=−0.14VE_{Fe^{3 +}/Fe^{2 +}}^{0} = + 0.77V; E_{Sn^{2 +}/Sn}^{0} = - 0.14V Under

standard conditions, the cell potential for the reaction given below is :

Sn(s) + 2Fe3+(aq)→2Fe2+(aq) + Sn2+(aq)\text{S}\text{n}_{(s)}\text{ + 2F}{\text{e}^{\text{3+}}}_{(\text{aq})} \rightarrow \text{2F}{\text{e}^{\text{2+}}}_{(\text{aq})}\text{ + S}{\text{n}^{\text{2+}}}_{(\text{aq})}

A

1.68 V

B

1.40 V

C

0.91 V

D

0.63 V

Answer

0.91 V

Explanation

Solution

E0cell = 0.77 + 0.14 = 0.91 volt.{E^{0}}_{\text{cell}}\text{ = 0.77 + 0.14 = 0.91 volt.}