Question
Mathematics Question on Graphical Representation of Data
The following data on the number of girls (to the nearest ten) per thousand boys in different sections of Indian Society is given below:Section | Number of girls per thousand boys |
---|---|
Scheduled Caste (SC) | 940 |
Scheduled Tribe (ST) | 970 |
Non-SC/ST | 920 |
Backward districts | 950 |
Non-backward districts | 920 |
Rural | 930 |
Urban | 910 |
(i) Represent the information above by a bar graph.
(ii) In the classroom discuss what conclusions can be arrived at from the graph.
(i) We represent the given information in the form of a bar graph. We construct the bar diagram through the following steps:
Step 1. Draw two perpendicular axes OX and OY on a plane paper.
Step 2. Along OX mark “Section” and along OY mark “Number of girls per thousand boys”.
Step 3. Along OX choose suitable width for each bar.
Step 4. Along OY choose an appropriate scale. Here choose 1 large division = 100 girls
Step 5. Calculate the heights of the various bars as follows:
(a) Height of bar for Scheduled caste =1001 x 940 = 9.4 large divisions
(b) Height of bar for Scheduled tribe =1001 x 970 = 9.7 large divisions
(c) Height of bar for Non SC / ST = 1001 x 920 = 9.2 large divisions
(d) Height of bar for Backward districts = 1001 x 950 = 9.5 large divisions
(e) Height of bar for non-backward districts = 1001 x 920 = 9.2 large divisions
(f) Height of bar for Rural = 1001 x 930 = 9.3 large divisions
(g) Height of bar for Urban =1001 x 910 = 9.1 large divisions
(ii) From the graph we observe that in each section the number of girls are nearly same. We also observe that the number of girls in each section are less than the boys. Also, it is observed that the number of girls to the nearest ten per thousand boys are maximum in scheduled tribes whereas they are minimum in urban areas.