Question

The focus of the parabola $( y + 1)^2 = -8(x +2)$ is

• A. (-4, -1)
• B. (-1, -4)
• C. (1, 4)
• D. (4, 1)

Answer 1

Answer: (A)

(-4, -1)

Answer 2

Given, $(y+1)^{2}=-8(x+2)$ $Y^{2}=-8 X$ ...(i) Here, $Y=y+1, \, X=(x+2)$ Vertices $(X=0, Y=0)=(-2,-1)$ Comparing E (i) from $y^{2}=4 ax$ $4 a=-8$ $a=-2$ Focus $=(-2-2,-1)$ $=(-4,-1)$