Question

The focal chord to y² = 16x is tangent to (x – 6)² + y² = 2, then the possible values of the slope of this chord, are-

• A. {–1, 1}
• B. {–2, 2}
• C. $\left\{ - 2,\frac{1}{2} \right\}$
• D. $\left\{ 2, - \frac{1}{2} \right\}$

Answer 1

Answer: (A)

{–1, 1}

Answer 2

y² = 16 x … (1)

ocus F (a, 0) ̃ (4, 0)

\ equation of focal chord

̃ y – 0 = m (x – 4)

̃ mx – y – 4m = 0 …. (2)

Q (x – 6)² + y² = 2 ….(3)

̃ c₁ (6, 0)

r = $\sqrt { 2 }$

̃ ₁N= r ̃ m = ?