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Question: The flow of blood in a larger artery of an anesthetized dog is diverted through a venturi meter. The...

The flow of blood in a larger artery of an anesthetized dog is diverted through a venturi meter. The wider part of the meter has a cross-sectional area equal to that of the artery A=8mm2A = 8m{m^2}. The narrower part has area a=4mm2a = 4m{m^2}. The pressure drop in the artery is 24Pa24Pa. What is the speed of the blood in the artery? Density of blood is 1.6×103kg/m31.6 \times {10^3}kg/{m^3}
A)13.5×102m/s13.5 \times {10^{ - 2}}m/s
B) 12.5×102m/s12.5 \times {10^{ - 2}}m/s
C) 26.5×102m/s26.5 \times {10^{ - 2}}m/s
D) 32.5×102m/s32.5 \times {10^{ - 2}}m/s

Explanation

Solution

The working of the venturi meter is based on the principle of Bernoulli’s equation. Use the equation of continuity of fluid in order to find the relation between the velocities of blood at the two parts of the artery. Then use Bernoulli’s equation to find the velocity.
Bernoulli’s equation is given by the formula,
P+ρgH+12ρV2=p+ρgh+12ρv2P + \rho gH + \dfrac{1}{2}\rho {V^2} = p + \rho gh + \dfrac{1}{2}\rho {v^2}

Complete step by step solution:

The area at the first part of artery is AAand at the second part of the artery is aa
Let the velocity of blood at the first part be VVand at the second part be vv
Law of continuity states that the volume of fluid entering in the pipe is equal to the volume of fluid leaving the pipe.
So,
By equation of continuity,
AV=avAV = av
8×V=4×v8 \times V = 4 \times v
2V=v2V = v
Let it be equation 1.
Now,
Bernoulli’s equations states that,
P+ρgH+12ρV2=p+ρgh+12ρv2P + \rho gH + \dfrac{1}{2}\rho {V^2} = p + \rho gh + \dfrac{1}{2}\rho {v^2}
Where,
P is the pressure of fluid at part 1
P is the pressure of fluid at part 2
H is the height of the pipe at part 1
h is the height of pipe at part 2
but,
there is nothing given about the height of the artery so we assume H=hH = h
the equation becomes
Pp=12ρ(V2v2)P - p = \dfrac{1}{2}\rho ({V^2} - {v^2})
PpP - p is the difference in the pressure and is equal to 24Pa24Pa according to the question.
ρ\rho is the density of blood
24=12×1.06×103×(4v2v2)24 = \dfrac{1}{2} \times 1.06 \times {10^3} \times (4{v^2} - {v^2})
v=12.5×102m/sv = 12.5 \times {10^{ - 2}}m/s

\therefore The speed of the blood in the artery is 12.5×102m/s12.5 \times {10^{ - 2}}m/s. So, option (B) is correct.

Note:
The flow of blood in the arteries is laminar flow. This is the reason we are able to use Bernoulli’s equation for this problem. This equation is only valid in the case of laminar flow.